Ricapitolando:
function display_item_details($IMAGE_URL,$site_area){
global $max_img_width,$designs_img_path,$site_currency,$LANG;
$CAT_DATA = $this->get_cat_data();
if(isset($_GET['aid']))
{
$param1 = $_GET['aid'];
$db_name = $CAT_DATA
;
$IMAGE_URL = "$IMAGE_URL" . $CAT_DATA[image_url];
$IMAGE_PATH = 'images/' . $CAT_DATA[image_path];
$Main_Cat_ID = $_GET['mid'];
$the_details = NULL;
$details = db::select_details($db_name,$param1,$site_area);
$cat = mysql_result($details,0,"cat");
$title = mysql_result($details,0,"title");
$description = mysql_result($details,0,"description");
$picture_1 = mysql_result($details,0,"picture_1");
$picture_2 = mysql_result($details,0,"picture_2");
$picture_3 = mysql_result($details,0,"picture_3");
$price = mysql_result($details,0,"price");
$time = mysql_result($details,0,"time");
$fname = mysql_result($details,0,"fname");
$lname = mysql_result($details,0,"lname");
$town = mysql_result($details,0,"town");
$google_maps = mysql_result($details,0,"google_maps");
$uid = mysql_result($details,0,"uid");
$the_title = $title;
$the_details = "<b>".$LANG['LG_DETAILS:'].' '.$the_title."</b>";
come faccio a ottenere il titolo della pagina???
visto che questo qua sotto non va??
<title><?php echo $title;?></title>
grazie a chi ha partecipato e a chi parteciperà alla discussione
