ho corretto un comando che mi dava un errore, ma subito se ne presentano altri.
<?php
session_start();
?>
<html>
<head>
<body onLoad="setTimeout('document.step1.submit();', 3000);">
<form name="step1" action="step1.php" method="get">
<title>Step1foto</title>
</head>
<?php
$connessione=mysql_connect("localhost", "");
$selezione_db=mysql_select_db("guest_book", $connessione);
$query = mysql_query("SELECT id_user, data FROM messaggi ORDER BY date DESC limit 1");
while($riga = mysql_fetch_assoc($query)) Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in c:\programmi\easyphp1-8\www\step1foto.php on line 25
{
$id_user = $riga['id_user'];
echo $riga["id_user"];
}
$nr_immagine = ($id_user - 1) * 10 + 1 + $offset; Notice: Undefined variable: id_user in c:\programmi\easyphp1-8\www\step1foto.php on line 31
Notice: Undefined variable: offset in c:\programmi\easyphp1-8\www\step1foto.php on line 31
$directory = "C:\Programmi\EasyPHP1-8\www\fotos";
$image_src = $directory . "image" . $nr_immagine . ".jpg"; Notice: Undefined variable: offset in c:\programmi\easyphp1-8\www\step1foto.php on line 37
echo "<img src="$image_src">"; Notice: Undefined variable: offset in c:\programmi\easyphp1-8\www\step1foto.php on line 38
if($offset < 50) {
$offset++; }
?>
<?php
$_SESSION['user'] = $_GET['user'];
$_SESSION['gender'] = $_GET['gender'];
$_SESSION['year'] = $_GET['year'];
$_SESSION['month'] = $_GET['month'];
$_SESSION['day'] = $_GET['day'];
$_SESSION['country'] = $_GET['country'];
?>
</body>
</html>