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errore queryciao a tutti! [PHP]<?php 
 mysql_query("SET CHARACTER SET utf8");
 mysql_query("SET NAMES utf8");
 $rowsPerPage = 20;
 $pageNum = 1;
 if (isset($_GET['page'])) {
 $pageNum = $_GET['page'];
 }
 $offset = ($pageNum - 1) * $rowsPerPage;
 $lettera=$_REQUEST['lettera'];
 if ($lettera == NULL) {
 $lettera = '';
 } else {
 $lettera=$_REQUEST['lettera'];
 }
 if ($spec == NULL and $lettera == NULL and $tipo_medico == 1) {
 $Sqlqr_gl="select * from medici_chirurghi where cognome != '' order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi where cognome != ''";
 } else if ($spec == NULL and $lettera != NULL and $tipo_medico == 1) {
 $Sqlqr_gl="select * from medici_chirurghi where cognome != '' and cognome LIKE '$lettera%' order by cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi where cognome != '' and cognome LIKE '$lettera%'";
 } else if ($spec != NULL and $tipo_medico == 1) {
 $Sqlqr_gl="select m.* from medici_chirurghi m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_chirurghi m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola";
 } else if ($spec == NULL and $lettera == NULL and $tipo_medico == 2) {
 $Sqlqr_gl="select * from medici_odontoiatri where cognome != '' order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri where cognome != ''";
 } else if ($spec == NULL and $lettera != NULL and $tipo_medico == 2) {
 $Sqlqr_gl="select * from medici_odontoiatri where cognome != '' and cognome LIKE '$lettera%' order by cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri where cognome != '' and cognome LIKE '$lettera%'";
 } else if ($spec != NULL and $tipo_medico == 2) {
 $Sqlqr_gl="select m.* from medici_odontoiatri m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola order by IF (ASCII(LOWER(cognome)) >=ASCII (LOWER('$lettera')),1,2),cognome LIMIT $offset, $rowsPerPage";
 $query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri m, matricola_specialita ms, specialita2 s where cognome != '' and s.id_spec = $spec and s.id_spec = ms.id_specialita and m.matricola2 = ms.matricola";
 }
 echo "<div style=display:none>".$Sqlqr_gl."</div>";
 $qr_gl=mysql_query($Sqlqr_gl,$connessione)or die(mysql_error());
 while($r_gl=mysql_fetch_array($qr_gl,MYSQL_ASSOC)) {
 if ($r_gl['cognome'] != NULL) {
 ?>[/PHP][PHP]<?php 
 if ($idmenu == '44') {
 $tipo_medico = '2';
 } else if ($idmenu == '45') {
 $tipo_medico = '1';
 }
 $result=mysql_query($query) or die('Error, seconda query failed');
 $row=mysql_fetch_array($result, MYSQL_ASSOC);
 $numrows = $row['numrows'];
 $maxPage = ceil($numrows/$rowsPerPage);
 // print the link to access each page
 $self = $_SERVER['PHP_SELF'];
 $nav = '';
 for($page = 1; $page <= $maxPage; $page++) {
 if ($page == $pageNum) {
 $nav .= "<strong><a href='#'>.$page.</a></strong>"; // no need to create a link to current page
 } else {
 $nav .= " <a href="$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico">.$page.</a> ";
 }
 }
 if ($pageNum > 1) {
 $page = $pageNum - 1;
 $prev = " <a href="$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico"><</a> ";
 $first = " <a href="$self?page=1&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico">[First Page]</a> ";
 } else {
 $prev = ' '; // we're on page one, don't print previous link
 $first = ' '; // nor the first page link
 }
 if ($pageNum < $maxPage) {
 $page = $pageNum + 1;
 $next = " <a href="$self?page=$page&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico">></a> ";
 $last = " <a href="$self?page=$maxPage&idmenu=$idmenu&lettera=$lettera&spec=$spec&tipomedico=$tipo_medico">[Last Page]</a> ";
 } else {
 $next = ' '; // we're on the last page, don't print next link
 $last = ' '; // nor the last page link
 }
 ?>[/PHP]l errore è : Error, seconda query failed 
 mi potreste dare una mano? grazie a tutti
 
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							Ciao, 
 invece di:
 [PHP]
 $result=mysql_query($query) or die('Error, seconda query failed');
 [/PHP]metti: 
 [PHP]
 $result=mysql_query($query) or die('Error, seconda query failed: '.mysql_error());
 [/PHP]In maniera tale da visualizzare l'errore generato. 
 
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l errore è: 
 Unknown column 'm.id_albo' in 'field list'grazie 
 
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							L'errore è nelle query come questa: 
 [PHP]$query="SELECT COUNT(m.id_albo) AS numrows from medici_odontoiatri where cognome != '' and cognome LIKE '$lettera%'";[/PHP]Dove non esiste m